The set representing the correct order of ion | vedclass

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(D) Ionic radius depends on the number of shells and the effective nuclear charge. $Na^{+}$ $(1s^2 2s^2 2p^6)$ has $3$ shells,while $Li^{+}$,$Mg^{2+}$

Vedclass · Accepted Answer

$Na^{+} > Li^{+} > Mg^{2+} > Be^{2+}$

Vedclass · Answer

(D) Ionic radius depends on the number of shells and the effective nuclear charge. $Na^{+}$ $(1s^2 2s^2 2p^6)$ has $3$ shells,while $Li^{+}$,$Mg^{2+}$,and $Be^{2+}$ have $2$ shells. Among ions with $2$ shells ($Li^{+}$,$Mg^{2+}$,$Be^{2+}$),the ionic radius decreases as the positive charge increases. $Li^{+}$ $(Z=3)$ has the lowest charge,followed by $Mg^{2+}$ ($Z=12$,but smaller due to higher charge),and $Be^{2+}$ $(Z=4)$ is the smallest. Thus,the correct order is $Na^{+} > Li^{+} > Mg^{2+} > Be^{2+}$.

The set representing the correct order of ionic radius is:

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