The area of the triangle formed by the lines | vedclass

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(B) The lines $x = 0$ (y-axis) and $y = 0$ (x-axis) intersect at the origin $(0, 0)$.The line $\frac{x}{a} + \frac{y}{b} = 1$ intersects the x-axis at

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$\frac{ab}{2}$

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(B) The lines $x = 0$ (y-axis) and $y = 0$ (x-axis) intersect at the origin $(0, 0)$.The line $\frac{x}{a} + \frac{y}{b} = 1$ intersects the x-axis at $(a, 0)$ and the y-axis at $(0, b)$.This forms a right-angled triangle with base $a$ and height $b$.The area of the triangle is given by $\frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes a 	imes b = \frac{ab}{2}$.

The area of the triangle formed by the lines $x = 0, y = 0$ and $\frac{x}{a} + \frac{y}{b} = 1$ is

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