The area of the region enclosed by the curve $f(x)=\max \{\sin x, \cos x\},-\pi \leq x \leq \pi$ and the $x$-axis is
$2(\sqrt{2}+1)$
$2 \sqrt{2}(\sqrt{2}+1)$
$4(\sqrt{2})$
$4$
The area (in sq. units) of the region enclosed by the curves $y=x^{2}-1$ and $y=1-x^{2}$ is equal to
Let $f ( x )= |x -2|$ and $g ( x )= f ( f ( x )), x \in[0,4]$ Then $\int \limits_{0}^{3}(g(x)-f(x)) d x$ is equal to
The area (in sq. units) of the region $\left\{(x, y): 0 \leq y \leq x^{2}+1,0 \leq y \leq x+1\right.$ $\left.\frac{1}{2} \leq x \leq 2\right\}$ is
The area of the region $\left\{(x, y): x^2 \leq y \leq 8-x^2, y \leq 7\right\}$ is
The area (in sq. units) of the region $\{(x,y):y^2 \geq 2x\,and\,x^2+y^2 \leq 4x,x \geq 0,y \leq 0 \}$ is