The area of a square field is $69696 \text{ cm}^2$. Its diagonal will be equal to (in $\text{cm}$) (in $.296$)

  • A
    $313$
  • B
    $353$
  • C
    $373$
  • D
    $393$

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In $\triangle ABC,$ a line parallel to side $BC$ intersects sides $AB$ and $AC$ at points $D$ and $E$ respectively. Point $D$ divides $AB$ in the ratio $1:4.$ If the area of $\triangle ABC$ is $200 \text{ cm}^2,$ what is the area (in $\text{cm}^2$) of quadrilateral $DECB$?

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