The area of a parallelogram whose adjacent sides are $i - 2j + 3k$ and $2i + j - 4k$ is:

  • A
    $5\sqrt{3}$
  • B
    $10\sqrt{3}$
  • C
    $5\sqrt{6}$
  • D
    $10\sqrt{6}$

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For a triangle $ABC$,let $\vec{p}=\vec{BC}$,$\vec{q}=\vec{CA}$ and $\vec{r}=\vec{BA}$. If $|\vec{p}|=2\sqrt{3}$,$|\vec{q}|=2$ and $\cos \theta = \frac{1}{\sqrt{3}}$ where $\theta$ is the angle between $\vec{p}$ and $\vec{q}$,then $|\vec{p} \times (\vec{q}-3\vec{r})|^{2}+3|\vec{r}|^{2}$ is equal to:

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