The area enclosed by the ellipse 4x^2 + 9y^2 | vedclass

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(A) The given equation of the ellipse is $4x^2 + 9y^2 = 1$. Rewriting this in the standard form $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$,we get: $\frac

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$\frac{\pi}{6}$

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(A) The given equation of the ellipse is $4x^2 + 9y^2 = 1$. Rewriting this in the standard form $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$,we get: $\frac{x^2}{(1/2)^2} + \frac{y^2}{(1/3)^2} = 1$. Here,$a = \frac{1}{2}$ and $b = \frac{1}{3}$. The area of an ellipse is given by the formula $A = \pi ab$. Substituting the values,we get $A = \pi 	imes \frac{1}{2} 	imes \frac{1}{3} = \frac{\pi}{6}$ sq. units.

The area enclosed by the ellipse $4x^2 + 9y^2 = 1$ is . . . . . . sq. units.

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