The area bounded by the $x$-axis and the curve $y = \sin x$ between $x = 0$ and $x = \pi$ is:

Find the area under the curve $y=x^{4}$ bounded by the lines $x=1$,$x=5$ and the $x$-axis.

Area of the region bounded by $y=|x|$ and $y=-|x|+2$ is

The area of the region bounded by the curves $y = |x - 2|$,$x = 1$,$x = 3$ and the $x$-axis is

If $A$ is the area of the region bounded by the curve $y = \sqrt{3x + 4}$,the $x$-axis,and the lines $x = -1$ and $x = 4$,and $B$ is the area bounded by the curve $y^2 = 3x + 4$,the $x$-axis,and the lines $x = -1$ and $x = 4$,then $A:B$ is equal to:

The area of the region bounded by the curve $y = \cos x$,$x = 0$,and $x = \pi$ is