The aqueous solution of $CuCrO_4$ is green because it contains

  • A
    green $Cu^{2+}$ ions
  • B
    green $CrO_4^{2-}$ ions
  • C
    blue $Cu^{2+}$ ions and green $CrO_4^{2-}$ ions
  • D
    blue $Cu^{2+}$ ions and yellow $CrO_4^{2-}$ ions

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Similar Questions

The correct option$(s)$ regarding the complex $[Co(en)(NH_3)_3(H_2O)]^{3+}$ $(en = H_2NCH_2CH_2NH_2)$ is (are):
$A$. It has two geometrical isomers
$B$. It will have three geometrical isomers if bidentate 'en' is replaced by two cyanide ligands
$C$. It is paramagnetic
$D$. It absorbs light at longer wavelength as compared to $[Co(en)(NH_3)_4]^{3+}$

Which of the following statements is not correct?

Write down the $IUPAC$ name for each of the following complexes and indicate the oxidation state,electronic configuration,and coordination number. Also,give the stereochemistry and magnetic moment of the complex:
$(i)$ $K[Cr(H_2O)_2(C_2O_4)_2] \cdot 3H_2O$
$(ii)$ $[Co(NH_3)_5Cl]Cl_2$
$(iii)$ $CrCl_3(py)_3$
$(iv)$ $Cs[FeCl_4]$
$(v)$ $K_4[Mn(CN)_6]$

Difficult
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Total number of molecules/species from the following which will be paramagnetic is $........$
$O_2, O_2^{+}, O_2^{-}, NO, NO_2, CO, K_2[NiCl_4], [Co(NH_3)_6]Cl_3, K_2[Ni(CN)_4]$

Match the following Column-$I$ (Reaction) with Column-$II$ (colour of the product or nature):
Column-$I$ (Reaction)Column-$II$ (colour of the product or nature)
$(A)$ $FeCl_3(aq) + NH_3(aq) \rightarrow$$(I)$ Green ppt
$(B)$ $AgCl(aq) + NH_3(aq) \rightarrow$$(II)$ Deep blue
$(III)$ Brown ppt
$(IV)$ Colourless solution

The correct answer for the sequence $(A, B)$ is:

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