(A) For a simple harmonic oscillator,the potential energy $V$ at displacement $x$ is given by $V = \frac{1}{2} k x^2$,where $k = m \omega^2$.The kinet

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(A) For a simple harmonic oscillator,the potential energy $V$ at displacement $x$ is given by $V = \frac{1}{2} k x^2$,where $k = m \omega^2$.The kinetic energy $T$ at displacement $x$ is given by $T = \frac{1}{2} k (A^2 - x^2)$.Taking the ratio $\frac{V}{T}$:$\frac{V}{T} = \frac{\frac{1}{2} k x^2}{\frac{1}{2} k (A^2 - x^2)}$$\frac{V}{T} = \frac{x^2}{A^2 - x^2}$

Class 11 Physics Oscillations SHM of Simple Pendulum

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The angular velocity and the amplitude of a simple pendulum are $\omega$ and $A$ respectively. At a displacement $x$ from the mean position,its kinetic energy is $T$ and potential energy is $V$. Then the ratio $\frac{V}{T}$ is

A
$\frac{x^2}{A^2 - x^2}$
B
$\frac{A^2 - x^2}{x^2}$
C
$\frac{x^2 \omega^2}{A^2 - x^2}$
D
$\frac{A^2 - x^2}{x^2 \omega^2}$

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The angular velocity and the amplitude of a simple pendulum are $\omega$ and $A$ respectively. At a displacement $x$ from the mean position,its kinetic energy is $T$ and potential energy is $V$. Then the ratio $\frac{V}{T}$ is

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