The angle of prism is $5^o$ and its refractive indices for red and violet colours are $1.5$ and $1.6$ respectively. The angular dispersion produced by the prism is.....$^o$

White light is passed through a prism of angle $5^{\circ}$. If the refractive indices for red and blue colors are $1.641$ and $1.659$ respectively,the angular dispersion between them will be..... (in $^{\circ}$)

It was found that the refractive index of the material of a certain prism varied as $\mu = 1.5 + 0.004 / \lambda^{2}$,where $\lambda$ is the wavelength of light used to measure the refractive index. The same material was then used to construct a thin prism of apex angle $10^{\circ}$. Angles of minimum deviation $\delta_{m}$ of the prism were recorded for the sources with wavelengths $\lambda_{1}$ and $\lambda_{2}$,respectively. Then,

One face of a glass prism is silver-polished. $A$ light ray falls at an angle of $45^{\circ}$ on the other face. After refraction,it is subsequently reflected from the silvered face and then retraces its path. The refracting angle of the prism is $30^{\circ}$. The refractive index of the prism is:

When light of wavelength $\lambda$ is incident on an equilateral prism kept in its minimum deviation position,it is found that the angle of deviation equals the angle of the prism itself. The refractive index of the material of the prism for the wavelength $\lambda$ is,then

The refractive index of the material of a glass prism is $\sqrt{3}$. If the angle of minimum deviation is equal to the angle of the prism,then the angle of the prism is:
$\left(\cos 30^{\circ} = \frac{\sqrt{3}}{2} = \sin 60^{\circ}, \sin 30^{\circ} = \frac{1}{2} = \cos 60^{\circ}\right)$ (in $^{\circ}$)