The angle of elevation of a ladder leaning ag | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In the figure,the ladder is represented by $AC$,where $AC$ is the hypotenuse of the right-angled triangle $ABC$.The distance from the foot of the

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) In the figure,the ladder is represented by $AC$,where $AC$ is the hypotenuse of the right-angled triangle $ABC$.The distance from the foot of the ladder to the wall is $AB = 4.242 \ m$.Using the trigonometric ratio for cosine:$\cos 45^{\circ} = \frac{	ext{Adjacent}}{	ext{Hypotenuse}} = \frac{AB}{AC}$$\frac{1}{\sqrt{2}} = \frac{4.242}{AC}$$AC = 4.242 	imes \sqrt{2}$Given $\sqrt{2} \approx 1.414$,we have:$AC = 4.242 	imes 1.414 \approx 6 \ m$.Thus,the length of the ladder is $6 \ m$.

The angle of elevation of a ladder leaning against a wall is $45^{\circ},$ and the foot of the ladder is $4.242 \ m$ away from the wall. The length of the ladder is (in $m$):

Similar Questions

The angle of elevation of a tower from a distance of $100 \ m$ from its foot is $30^{\circ}$. Then the height of the tower is (in $m$):

From the top of a cliff,$60 \ m$ high,the angles of depression of the top and bottom of a tower are observed to be $30^{\circ}$ and $60^{\circ}$ respectively. Find the height of the tower in $m$.

$A$ tower subtends an angle of $30^{\circ}$ at a point on the same level as the foot of the tower. At a second point,$h \ m$ above the first,the angle of depression of the foot of the tower is $60^{\circ}$. The horizontal distance of the tower from the point is

If $r \sin \theta = 1$ and $r \cos \theta = \sqrt{3}$,then the value of $(\sqrt{3} \tan \theta + 1)$ is

The angle of elevation of the top of a tower from a point $20 \ m$ away from its base is $45^{\circ}$. The height of the tower is (in $m$):

Vedclass Test Series

Exam Paper Generator

Online Exam Module