The angle between the lines x cos 30^circ + y | vedclass

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(B) The given lines are in the normal form $x \cos \alpha + y \sin \alpha = p$.For the first line $x \cos 30^\circ + y \sin 30^\circ = 3$,the normal m

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$30$

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(B) The given lines are in the normal form $x \cos \alpha + y \sin \alpha = p$.For the first line $x \cos 30^\circ + y \sin 30^\circ = 3$,the normal makes an angle $\alpha_1 = 30^\circ$ with the positive $x$-axis.For the second line $x \cos 60^\circ + y \sin 60^\circ = 5$,the normal makes an angle $\alpha_2 = 60^\circ$ with the positive $x$-axis.The angle $	heta$ between two lines is equal to the angle between their normals.Therefore,$	heta = |\alpha_2 - \alpha_1| = |60^\circ - 30^\circ| = 30^\circ$.

The angle between the lines $x \cos 30^\circ + y \sin 30^\circ = 3$ and $x \cos 60^\circ + y \sin 60^\circ = 5$ is .....$^\circ$

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