The angle between the circles $x^2+y^2-4x-6y-3=0$ and $x^2+y^2+8x-4y+11=0$ is

  • A
    $\frac{\pi}{3}$
  • B
    $\frac{\pi}{6}$
  • C
    $\frac{\pi}{2}$
  • D
    $\frac{\pi}{4}$

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