The amplification factor of a triode is 20. I | vedclass

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Question

(D) The relationship between amplification factor $\mu$, plate resistance $r_p$, and mutual conductance $g_m$ is given by the formula: $\mu = r_p 	im

Vedclass · Accepted Answer

$2 	imes 10^{-3} \, 	ext{mho}$

Vedclass · Answer

(D) The relationship between amplification factor $\mu$, plate resistance $r_p$, and mutual conductance $g_m$ is given by the formula: $\mu = r_p 	imes g_m$.Given: $\mu = 20$ and $r_p = 10 \, k\Omega = 10 	imes 10^3 \, \Omega = 10^4 \, \Omega$.Rearranging the formula to solve for $g_m$: $g_m = \frac{\mu}{r_p}$.Substituting the values: $g_m = \frac{20}{10 	imes 10^3} = \frac{20}{10000} = 2 	imes 10^{-3} \, 	ext{mho}$ (or Siemens).Therefore, the correct option is $D$.

The amplification factor of a triode is $20$. Its plate resistance is $10 \, k\Omega$. The mutual conductance is:

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