The amplification factor of a triode is 50. I | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The amplification factor $\mu$ of a triode is defined as the ratio of the change in plate potential to the change in grid potential for a constant

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(B) The amplification factor $\mu$ of a triode is defined as the ratio of the change in plate potential to the change in grid potential for a constant plate current,with a negative sign indicating that the potentials must change in opposite directions to maintain the same current.$\mu = - \frac{\Delta V_p}{\Delta V_g}$Given: $\mu = 50$ and $\Delta V_g = -0.20\, V$.To keep the plate current unchanged,we need to find the required increase in plate potential $\Delta V_p$.$\Delta V_p = - \mu 	imes \Delta V_g$$\Delta V_p = -50 	imes (-0.20\, V) = 10\, V$.Therefore,an increase of $10\, V$ in plate potential is required.

The amplification factor of a triode is $50$. If the grid potential is decreased by $0.20\, V$,what increase in plate potential will keep the plate current unchanged?

Similar Questions

$A$ triode has a mutual conductance of $2 \times 10^{-3} \text{ mho}$ and an amplification factor of $50$. The anode is connected through a resistance of $25 \times 10^3 \, \Omega$ to a $250 \, \text{V}$ supply. The voltage gain of this amplifier is

In a triode amplifier,the value of maximum gain is equal to

The relation between $I_p$ and $V_p$ for a triode is $I_p = (0.125V_p - 7.5) \text{ mA}$. Keeping the grid potential constant at $1 \text{ V}$,the value of $r_p$ will be . . . . . . $\text{k}\Omega$.

The amplification factor of a triode is $20$. Its plate resistance is $10 \, k\Omega$. The mutual conductance is:

In a triode valve,which of the following statements is correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module