The amount of heat released when $20 \ mL$ of $0.5 \ M$ $NaOH$ is mixed with $100 \ mL$ of $0.1 \ M$ $HCl$ is $x \ kJ$. The heat of neutralization is:

  • A
    $-100 \ x \ kJ / mol$
  • B
    $-50 \ kJ / mol$
  • C
    $+100 \ x \ kJ / mol$
  • D
    $+50 \ kJ / mol$

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