The alternating current is given by

${i}=\left\{\sqrt{42} \sin \left(\frac{2 \pi}{{T}} {t}\right)+10\right\} {A}$

The $r.m.s.$ value of this current is ${A}$

A resistance of $40 \,\Omega$ is connected to a source of alternating current rated $220\, V , 50 Hz$. Find the time taken by the current to change from its maximum value to $ms$ value

An alternating voltage $\mathrm{V}(\mathrm{t})=220 \sin 100 \ \pi \mathrm{t}$ volt is applied to a purely resistive load of $50\ \Omega$. The time taken for the current to rise from half of the peak value to the peak value is:

The current flowing through an ac circuit is given by

$I=5 \sin (120 \pi t) A$

How long will the current take to reach the peak value starting from zero?

A periodic voltage $V$ varies with time $t$ as shown in the figure. $T$ is the time period. The $r.m.s$. value of the voltage is :-

In a circuit, the value of the alternating current is measured by hot wire ammeter as $10$ ampere. Its peak value will be......$A$