The alkene formed as a major product in the b | vedclass

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(D) The given reaction is a Hofmann elimination,which occurs when a quaternary ammonium salt is heated with a base like $OH^-$.In Hofmann elimination,

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$CH_2=CH_2$

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(D) The given reaction is a Hofmann elimination,which occurs when a quaternary ammonium salt is heated with a base like $OH^-$.In Hofmann elimination,the base abstracts a proton from the $\beta$-carbon that is least sterically hindered,leading to the formation of the least substituted alkene as the major product.In the provided substrate,the quaternary nitrogen is attached to a methyl group,an ethyl group,a $n$-butyl group,and a cyclohexenyl ring.Comparing the $\beta$-hydrogens available:$1$. $\beta_1$ on the ethyl group leads to $CH_2=CH_2$ (ethene).$2$. $\beta_2$ on the $n$-butyl group leads to $CH_2=CHCH_2CH_3$ ($1$-butene).$3$. $\beta_3$ and $\beta_4$ on the ring lead to cyclic alkenes.According to the Hofmann rule,the least substituted alkene,which is $CH_2=CH_2$ (ethene),is formed as the major product because the ethyl group is the least sterically hindered group attached to the nitrogen.

The alkene formed as a major product in the below elimination reaction is

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\begin{array}{c}
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