The given reaction is a pinacol-pinacolone re | vedclass

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(A) The reaction is a pinacol-pinacolone rearrangement of $1,1'-bi(cyclopentane)-1,1'-diol$. Upon treatment with $conc. H_2SO_4$ and heat,one of the h

Vedclass · Accepted Answer

It is a spiro compound

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(A) The reaction is a pinacol-pinacolone rearrangement of $1,1'-bi(cyclopentane)-1,1'-diol$. Upon treatment with $conc. H_2SO_4$ and heat,one of the hydroxyl groups is protonated and leaves as water,forming a carbocation. Then,a ring contraction or rearrangement occurs to form a ketone. The product formed is $cyclopentyl-cyclopentanone$ (specifically,$2-cyclopentylcyclopentanone$). $A$. It is not a spiro compound; it is a bicyclic ketone where one cyclopentyl ring is attached to the other. $B$. It is a ketone. $C$. It can show tautomerism because it has $\alpha$-hydrogens. $D$. The double bond equivalent $(DBE)$ for $C_{10}H_{16}O$ is $10 - (16/2) + 1 = 3$. Thus,the statement that $DBE = 4$ is incorrect.

The given reaction is a pinacol-pinacolone rearrangement. Which of the following is not correct about the product formed?

Similar Questions

Identify the product and the name of the reaction for the following transformation:
$
\begin{array}{c}
\text{Decalin-1-one oxime} \rightarrow{H_2SO_4} \text{Product}
\end{array} $
(The starting material is a ketoxime derived from decalin$-1-$one with a methyl group at the alpha position).

Ionic reactions with organic compounds proceed through:
$(A)$ Homolytic bond cleavage
$(B)$ Heterolytic bond cleavage
$(C)$ Free radical formation
$(D)$ Primary free radical
$(E)$ Secondary free radical
Choose the correct answer from the options given below:

Based on the provided energy profile diagram,transition state $2$ $(T.S. 2)$ is structurally most likely similar to which of the following?

An organic compound $A$,$C_5 H_8 O$,reacts with $H_2 O$,$NH_3$,and $CH_3 COOH$ as shown in the reaction scheme. Identify $A$.

What is the fission of covalent bonds?

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