The air density at Mount Everest is less than | vedclass

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(A) The number of moles of gas remains constant in both conditions.Using the ideal gas law equation: $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.Given

Vedclass · Accepted Answer

$3.86$

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(A) The number of moles of gas remains constant in both conditions.Using the ideal gas law equation: $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.Given at sea level: $P_1 = 1 \ atm$,$V_1 = 30,000 \ cc = 30 \ L$,$T_1 = 27 + 273 = 300 \ K$.Given at Mount Everest: $V_2 = 5.2 \ L$,$T_2 = -73 + 273 = 200 \ K$.Substituting the values: $\frac{1 	imes 30}{300} = \frac{P_2 	imes 5.2}{200}$.$0.1 = \frac{P_2 	imes 5.2}{200}$.$P_2 = \frac{0.1 	imes 200}{5.2} = \frac{20}{5.2} \approx 3.846 \ atm$.Rounding to the nearest option,$P_2 \approx 3.86 \ atm$.

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