If the equation $2x^2 + kxy - 6y^2 + 3x + y + 1 = 0$,$(k > 0)$ represents a pair of straight lines,then their point of intersection is

  • A
    $\left(\frac{5}{8}, \frac{1}{8}\right)$
  • B
    $\left(\frac{5}{8}, \frac{-1}{8}\right)$
  • C
    $\left(\frac{-5}{8}, \frac{-1}{8}\right)$
  • D
    $\left(\frac{-5}{8}, \frac{1}{8}\right)$

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Let $\overrightarrow{a}=a_1 \hat{i}+a_2 \hat{j}+a_3 \hat{k}$.
Assertion $(A)$: The identity $|\overrightarrow{a} \times \hat{i}|^2+|\overrightarrow{a} \times \hat{j}|^2+|\overrightarrow{a} \times \hat{k}|^2=2|\overrightarrow{a}|^2$ holds for $\overrightarrow{a}$.
Reason $(R)$: $\overrightarrow{a} \times \hat{i}=a_3 \hat{j}-a_2 \hat{k}$,$\overrightarrow{a} \times \hat{j}=a_1 \hat{k}-a_3 \hat{i}$,and $\overrightarrow{a} \times \hat{k}=a_2 \hat{i}-a_1 \hat{j}$.
Which of the following is correct?

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