The addition of HBr to 2-pentene gives | vedclass

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(C) The reaction of $HBr$ with $2-$pentene $(CH_3-CH=CH-CH_2-CH_3)$ is an electrophilic addition reaction.According to Markovnikov's rule,the proton $

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$2-$bromopentane and $3-$bromopentane

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(C) The reaction of $HBr$ with $2-$pentene $(CH_3-CH=CH-CH_2-CH_3)$ is an electrophilic addition reaction.According to Markovnikov's rule,the proton $(H^+)$ adds to the carbon atom of the double bond that already has more hydrogen atoms,or in this case,to form the more stable carbocation intermediate.$2-$pentene is a symmetrical alkene with respect to the double bond position relative to the chain ends,but the two carbons of the double bond are not equivalent.Protonation at $C_2$ gives a secondary carbocation at $C_3$ $(CH_3-CH^+-CH_2-CH_2-CH_3)$,and protonation at $C_3$ gives a secondary carbocation at $C_2$ $(CH_3-CH_2-CH^+-CH_2-CH_3)$.Both carbocations are secondary and have similar stability.Therefore,the bromide ion $(Br^-)$ can attack either carbocation,resulting in a mixture of $2-$bromopentane and $3-$bromopentane.

The addition of $HBr$ to $2-$pentene gives

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