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(C) The electric flux $\Phi_E$ is defined as the product of the electric field $E$ and the area $A$ through which it passes,given by $\Phi_E = E \cdot

Vedclass · Accepted Answer

Volt $	imes$ metre

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(C) The electric flux $\Phi_E$ is defined as the product of the electric field $E$ and the area $A$ through which it passes,given by $\Phi_E = E \cdot A$.The $S.I.$ unit of electric field $E$ is $	ext{Newton per coulomb}$ $(N/C)$ or $	ext{Volt per metre}$ $(V/m)$.The $S.I.$ unit of area $A$ is $	ext{square metre}$ $(m^2)$.Therefore,the $S.I.$ unit of electric flux is $\frac{N}{C} 	imes m^2 = \frac{N \cdot m^2}{C}$.Since $1 	ext{ Joule} = 1 	ext{ Newton} 	imes 1 	ext{ metre}$,we can write $\frac{N \cdot m^2}{C} = \frac{J \cdot m}{C}$.Since $1 	ext{ Volt} = 1 	ext{ Joule per coulomb}$ $(J/C)$,the unit becomes $	ext{Volt} 	imes 	ext{metre}$ $(V \cdot m)$.

The $S.I.$ unit of electric flux is

Similar Questions

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