The r.m.s. velocity will be greater for | vedclass

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(A) The formula for $r.m.s.$ velocity is given by $v_{rms} = \sqrt{\frac{3RT}{M}}$.From this relation,we can see that $v_{rms} \propto \frac{1}{\sqrt{

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Hydrogen

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(A) The formula for $r.m.s.$ velocity is given by $v_{rms} = \sqrt{\frac{3RT}{M}}$.From this relation,we can see that $v_{rms} \propto \frac{1}{\sqrt{M}}$,assuming temperature $T$ and gas constant $R$ are constant.Comparing Hydrogen $(H_2)$ and Oxygen $(O_2)$,the molar mass of Hydrogen $(M_{H_2} \approx 2 \ g/mol)$ is significantly lower than the molar mass of Oxygen $(M_{O_2} \approx 32 \ g/mol)$.Since the $r.m.s.$ velocity is inversely proportional to the square root of the molar mass,the gas with the lower molecular mass will have a higher $r.m.s.$ velocity.Therefore,the $r.m.s.$ velocity will be greater for Hydrogen.

The $r.m.s.$ velocity will be greater for

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