The X and Y components of a force F acting at | vedclass

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(D) The components of a force $F$ acting at an angle $	heta$ with the $x$-axis are given by $F_{x} = F \cos 	heta$ and $F_{y} = F \sin 	heta$.Given

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$\frac{\sqrt{3}}{2} F, \frac{1}{2} F$

Vedclass · Answer

(D) The components of a force $F$ acting at an angle $	heta$ with the $x$-axis are given by $F_{x} = F \cos 	heta$ and $F_{y} = F \sin 	heta$.Given $	heta = 30^{\circ}$,we have:$F_{x} = F \cos 30^{\circ} = F 	imes \frac{\sqrt{3}}{2} = \frac{\sqrt{3}}{2} F$.$F_{y} = F \sin 30^{\circ} = F 	imes \frac{1}{2} = \frac{1}{2} F$.Therefore,the $X$ and $Y$ components are $\frac{\sqrt{3}}{2} F$ and $\frac{1}{2} F$ respectively.

The $X$ and $Y$ components of a force $F$ acting at $30^{\circ}$ to the $x$-axis are respectively:

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