The H-C-H,H-N-H,and H-O-H bond angles (in deg | vedclass

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(B) The bond angle in a molecule is affected by the number of lone pairs and the electronegativity of the central atom.In $CH_4$ (methane),the central

Vedclass · Accepted Answer

$109.5, 107.1, 104.5$

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(B) The bond angle in a molecule is affected by the number of lone pairs and the electronegativity of the central atom.In $CH_4$ (methane),the central carbon atom has $4$ bonding pairs and $0$ lone pairs,resulting in a tetrahedral geometry with a bond angle of $109.5^{\circ}$.In $NH_3$ (ammonia),the central nitrogen atom has $3$ bonding pairs and $1$ lone pair. The lone pair-bond pair repulsion reduces the bond angle to $107.1^{\circ}$.In $H_2O$ (water),the central oxygen atom has $2$ bonding pairs and $2$ lone pairs. The greater lone pair-lone pair repulsion further reduces the bond angle to $104.5^{\circ}$.Therefore,the bond angles are $109.5^{\circ}, 107.1^{\circ}, 104.5^{\circ}$ respectively.

List-$I$ (species)	List-$II$ ($O-N-O$ angle)
$A$. $NO_2^+$	$1$. $180^{\circ}$
$B$. $NO_2$	$2$. $132^{\circ}$
$C$. $NO_2^-$	$3$. $115^{\circ}$
$D$. $NO_3^-$	$4$. $120^{\circ}$

The $H-C-H$,$H-N-H$,and $H-O-H$ bond angles (in $degrees$) in methane,ammonia,and water are respectively,closest to

Similar Questions

Match List-$I$ with List-$II$ and select the correct answer:

List-$I$ (species) List-$II$ ($O-N-O$ angle)

$A$. $NO_2^+$ $1$. $180^{\circ}$

$B$. $NO_2$ $2$. $132^{\circ}$

$C$. $NO_2^-$ $3$. $115^{\circ}$

$D$. $NO_3^-$ $4$. $120^{\circ}$

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