The EAN of iron in potassium ferricyanide is | vedclass

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Question

(C) The formula for $EAN$ is: $EAN = Z - 	ext{oxidation state} + (2 	imes 	ext{coordination number})$.In potassium ferricyanide,$K_3[Fe(CN)_6]$,the

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$35$

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(C) The formula for $EAN$ is: $EAN = Z - 	ext{oxidation state} + (2 	imes 	ext{coordination number})$.In potassium ferricyanide,$K_3[Fe(CN)_6]$,the iron is in the $+3$ oxidation state.The atomic number $(Z)$ of iron $(Fe)$ is $26$.The coordination number of $Fe$ in $[Fe(CN)_6]^{3-}$ is $6$.Therefore,$EAN = 26 - 3 + (2 	imes 6) = 23 + 12 = 35$.

The $EAN$ of iron in potassium ferricyanide is

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