The LCM of 2^{2} times 3^{2} times 5 times 11 | vedclass

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(B) To find the $LCM$ of numbers given in prime factorization form,we take the highest power of each prime factor present in any of the numbers.The gi

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$2^{5} 	imes 3^{4} 	imes 5^{2} 	imes 7^{2} 	imes 11$

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(B) To find the $LCM$ of numbers given in prime factorization form,we take the highest power of each prime factor present in any of the numbers.The given numbers are:$1) \ 2^{2} 	imes 3^{2} 	imes 5^{1} 	imes 11^{1}$$2) \ 2^{4} 	imes 3^{4} 	imes 5^{2} 	imes 7^{1}$$3) \ 2^{5} 	imes 3^{3} 	imes 5^{2} 	imes 7^{2} 	imes 11^{1}$Identifying the highest powers of each prime factor:- For $2$: The highest power is $2^{5}$.- For $3$: The highest power is $3^{4}$.- For $5$: The highest power is $5^{2}$.- For $7$: The highest power is $7^{2}$.- For $11$: The highest power is $11^{1}$.Therefore,the $LCM = 2^{5} 	imes 3^{4} 	imes 5^{2} 	imes 7^{2} 	imes 11^{1}$.

The $LCM$ of $2^{2} \times 3^{2} \times 5 \times 11$,$2^{4} \times 3^{4} \times 5^{2} \times 7$,and $2^{5} \times 3^{3} \times 5^{2} \times 7^{2} \times 11$ is:

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