The CFSE for [CoCl_6]^{4-} complex is 18000 | vedclass

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(D) The relationship between octahedral splitting energy $(\Delta_0)$ and tetrahedral splitting energy $(\Delta_t)$ is given by the formula: $\Delta_t

Vedclass · Accepted Answer

$8000$

Vedclass · Answer

(D) The relationship between octahedral splitting energy $(\Delta_0)$ and tetrahedral splitting energy $(\Delta_t)$ is given by the formula: $\Delta_t = \frac{4}{9} \Delta_0$. Given that for the octahedral complex $[CoCl_6]^{4-}$,$\Delta_0 = 18000 \ cm^{-1}$. Substituting this value into the formula: $\Delta_t = \frac{4}{9} 	imes 18000 \ cm^{-1}$. $\Delta_t = 4 	imes 2000 \ cm^{-1} = 8000 \ cm^{-1}$.

The $CFSE$ for $[CoCl_6]^{4-}$ complex is $18000 \ cm^{-1}$. The $\Delta_t$ for $[CoCl_4]^{2-}$ will be ........... $cm^{-1}$.

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