The IUPAC name of the compound with the formu | vedclass

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(C) $1$. Identify the longest carbon chain containing the double bond. The chain has $4$ carbon atoms,so the parent alkane is butane,and with the doub

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$3,3-$Dimethylbut$-1-$ene

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(C) $1$. Identify the longest carbon chain containing the double bond. The chain has $4$ carbon atoms,so the parent alkane is butane,and with the double bond,it is but$-1-$ene.$2$. Number the chain starting from the end closest to the double bond to give it the lowest possible locant. Thus,$C_1=CH_2$,$C_2=CH$,$C_3=C(CH_3)_2$,and $C_4=CH_3$.$3$. There are two methyl groups attached at the $C_3$ position.$4$. Combining these,the name is $3,3-$Dimethylbut$-1-$ene.

List-$I$ (structure)	List-$II$ ($IUPAC$ Name)
$A$. $CH_3CH_2CH(CH_2CH_3)CH_2CH(CH_3)CH_2CH_3$	$I$. $4-$Methylpent$-1-$ene
$B$. $(CH_3)_2C(C_3H_7)_2$	$II$. $3-$Ethyl$-5-$methylheptane
$C$. $CH_2=C(CH_3)CH=CHCH_3$	$III$. $4,4-$Dimethylheptane
$D$. $CH_2=CHCH_2CH(CH_3)CH_3$	$IV$. $2-$Methyl$-1,3-$pentadiene

The $IUPAC$ name of the compound with the formula $CH_3-C(CH_3)_2-CH=CH_2$ is:

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