The r.m.s. value of an ac of 50,Hz is 10,amp | vedclass

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Question

Time taken by alternating current to reach maximum from zero is $\frac{T}{4}$

where $T$ is the time period of the $AC$ function.

$T=\frac{1}{f},

Vedclass · Accepted Answer

$5 	imes 10^{-3}\,sec$ and $14.14\,amp$

Vedclass · Answer

Time taken by alternating current to reach maximum from zero is $\frac{T}{4}$

where $T$ is the time period of the $AC$ function.

$T=\frac{1}{f},$ Frequency $(f)=50 \mathrm{Hz}$

So time taken to reach maximum $=\frac{T}{4}=\frac{1}{4 f}=\frac{1}{4 	imes 50}=5 	imes 10^{-3} \mathrm{sec}$

$I_{R M S}=\frac{I_{0}}{\sqrt{2}}, I_{0}=$ Peak value of current

Peak value of current $I_{0}=\sqrt{2} 	imes I_{R M S}=\sqrt{2} 	imes 10=14.14 \mathrm{A}$

The $r.m.s.$ value of an ac of $50\,Hz$ is $10\,amp$ . The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be

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