A complex current wave is given by i = 5 + 5, | vedclass

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(B) The given current equation is $i = 5 + 5\sin(100\, \omega t)$.The average value of the current over one complete time period $T$ is defined as $ =

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$5$

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(B) The given current equation is $i = 5 + 5\sin(100\, \omega t)$.The average value of the current over one complete time period $T$ is defined as $ = \frac{1}{T} \int_{0}^{T} i\, dt$.Substituting the expression for $i$: $ = \frac{1}{T} \int_{0}^{T} (5 + 5\sin(100\, \omega t))\, dt$.This can be split into two parts: $ = \frac{1}{T} \int_{0}^{T} 5\, dt + \frac{1}{T} \int_{0}^{T} 5\sin(100\, \omega t)\, dt$.The average value of a sine function over one complete cycle is $0$,i.e.,$\langle \sin(100\, \omega t) \rangle = 0$.Therefore,$ = 5 + 0 = 5\, A$.

$A$ complex current wave is given by $i = 5 + 5\, \sin(100\, \omega t)\, A$. Its average value over one complete time period is given as.....$A$.

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