Class 11MathematicsPermutation and CombinationDefinition of permutation, Number of permutations with or without repetition, Conditional permutations
EasyTen men and $6$ women are to be seated in a row so that no two women sit together. The number of ways they can be seated is:
- A$11! \times 10!$
- B$\frac{11!}{6! 5!}$
- C$\frac{10! 11!}{5!}$
- D$\frac{11! 10!}{6!}$
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$10$ men and $6$ women are to be seated in a row so that no two women sit together. The number of ways they can be seated is:
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