Suppose a population A has 100 observations 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The population $A$ consists of $100$ consecutive integers: $101, 102, . . ., 200$.The population $B$ consists of $100$ consecutive integers: $151,

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) The population $A$ consists of $100$ consecutive integers: $101, 102, . . ., 200$.The population $B$ consists of $100$ consecutive integers: $151, 152, . . ., 250$.We know that the variance of a set of observations is independent of the change of origin. That is,if $y_i = x_i + c$,then $Var(y) = Var(x)$.Here,each observation in population $B$ can be written as $y_i = x_i + 50$,where $x_i$ are the observations of population $A$.Since the variance is invariant under the change of origin,$V_A = V_B$.Therefore,$\frac{V_A}{V_B} = 1$.

Class Interval	Frequency
$0 - 6$	$10$
$6 - 12$	$8$
$12 - 18$	$6$
$18 - 24$	$4$
$24 - 30$	$2$

Class Interval	$0-10$	$10-20$	$20-30$	$30-40$
Frequency	$2$	$3$	$4$	$1$

Suppose a population $A$ has $100$ observations $101, 102, . . ., 200$ and another population $B$ has $100$ observations $151, 152, . . ., 250$. If $V_A$ and $V_B$ represent the variances of the two populations,respectively,then $V_A / V_B$ is:

Similar Questions

The variance of the following frequency distribution is
Class Interval Frequency
$0 - 6$ $10$
$6 - 12$ $8$
$12 - 18$ $6$
$18 - 24$ $4$
$24 - 30$ $2$

$A$ data consists of $20$ observations $x_1, x_2, ..., x_{20}$. If $\sum_{i=1}^{20} (x_i + 5)^2 = 2500$ and $\sum_{i=1}^{20} (x_i - 5)^2 = 100$,then the ratio of mean to standard deviation of this data is:

The mean and variance of $10$ observations were calculated as $15$ and $15$ respectively by a student who took by mistake $25$ instead of $15$ for one observation. Then,the correct standard deviation is $.....$

The coefficient of variation for the following data is
Class interval $0-2$ $2-4$ $4-6$ $6-8$ $8-10$
Frequency $2$ $3$ $5$ $3$ $2$

The variance of the following continuous frequency distribution is
Class Interval $0-10$ $10-20$ $20-30$ $30-40$
Frequency $2$ $3$ $4$ $1$

Vedclass Test Series

Exam Paper Generator

Online Exam Module