Suppose a planet exists whose mass and radius | vedclass

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(B) Given that the mass of the planet $M_P = M/2$ and the radius of the planet $R_P = R/2$,where $M$ and $R$ are the mass and radius of the Earth resp

Vedclass · Accepted Answer

$2g$

Vedclass · Answer

(B) Given that the mass of the planet $M_P = M/2$ and the radius of the planet $R_P = R/2$,where $M$ and $R$ are the mass and radius of the Earth respectively.The formula for acceleration due to gravity on the surface of a planet is $g = GM/R^2$.For the given planet,the acceleration due to gravity $g_P$ is given by:$g_P = \frac{GM_P}{R_P^2}$Substituting the values $M_P = M/2$ and $R_P = R/2$:$g_P = \frac{G(M/2)}{(R/2)^2} = \frac{GM/2}{R^2/4} = \frac{GM}{2} 	imes \frac{4}{R^2} = 2 	imes \frac{GM}{R^2}$Since $g = GM/R^2$,we get:$g_P = 2g$Therefore,the acceleration due to gravity on the surface of this planet is $2g$.

Suppose a planet exists whose mass and radius both are half that of Earth. Calculate the acceleration due to gravity on the surface of this planet.

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