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(B) To find the neighbours that are farthest in alphabetical order,we calculate the absolute difference between the positions of adjacent letters in t

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$D$ and $Y$

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(B) To find the neighbours that are farthest in alphabetical order,we calculate the absolute difference between the positions of adjacent letters in the English alphabet $(A=1, B=2, ..., Z=26)$:$1$. $(H, D): |8 - 4| = 4$$2$. $(D, Y): |4 - 25| = 21$$3$. $(Y, S): |25 - 19| = 6$$4$. $(S, M): |19 - 13| = 6$$5$. $(M, W): |13 - 23| = 10$$6$. $(W, N): |23 - 14| = 9$$7$. $(N, B): |14 - 2| = 12$$8$. $(B, Q): |2 - 17| = 15$$9$. $(Q, P): |17 - 16| = 1$$10$. $(P, O): |16 - 15| = 1$$11$. $(O, C): |15 - 3| = 12$$12$. $(C, R): |3 - 18| = 15$$13$. $(R, T): |18 - 20| = 2$$14$. $(T, B): |20 - 2| = 18$$15$. $(B, L): |2 - 12| = 10$$16$. $(L, Z): |12 - 26| = 14$$17$. $(Z, V): |26 - 22| = 4$$18$. $(V, E): |22 - 5| = 17$$19$. $(E, G): |5 - 7| = 2$$20$. $(G, U): |7 - 21| = 14$$21$. $(U, F): |21 - 6| = 15$Comparing all differences,the pair $(D, Y)$ has the maximum difference of $21$.

Study the letter series given below and answer the questions that follow:
$H, D, Y, S, M, W, N, B, Q, P, O, C, R, T, B, L, Z, V, E, G, U, F$
Which two neighbours in the given arrangement are farthest in the alphabetical order?

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Study the letter series given below and answer the questions that follow:$H, D, Y, S, M, W, N, B, Q, P, O, C, R, T, B, L, Z, V, E, G, U, F$Which two neighbours in the given arrangement are farthest in the alphabetical order?