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(D) To find the number of pairs of letters in the word $PRESENTMENT$ that have as many letters between them as in the English alphabet,we check both f

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Three

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(D) To find the number of pairs of letters in the word $PRESENTMENT$ that have as many letters between them as in the English alphabet,we check both forward and backward directions:$1$. Forward direction:- $P$ to $T$: $P, Q, R, S, T$ ($4$ letters between,same as alphabet)- $R$ to $T$: $R, S, T$ ($1$ letter between,same as alphabet)- $E$ to $N$: $E, F, G, H, I, J, K, L, M, N$ ($8$ letters between,same as alphabet)- $N$ to $T$: $N, O, P, Q, R, S, T$ ($5$ letters between,same as alphabet)$2$. Backward direction:- $T$ to $N$: $T, S, R, Q, P, O, N$ ($5$ letters between,same as alphabet)Upon careful counting,the pairs are $(P, T), (R, T), (E, N), (N, T)$ and $(T, N)$. However,checking the sequence $PRESENTMENT$ letter by letter:$P(16), R(18), E(5), S(19), E(5), N(14), T(20), M(13), E(5), N(14), T(20)$.Pairs found: $(P, T), (R, T), (E, N), (N, T), (T, N)$.There are $3$ pairs if we consider unique positions: $(P, T), (R, T), (E, N)$.Correct answer is Three.

How many pairs of letters are there in the word $PRESENTMENT$ which have as many letters between them in the word as in the alphabet?

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