Students of two sections $A$ and $B$ of a class show the following results in a test conducted for $100$ marks. Then
Section $A$ Section $B$ Number of students $50$ $60$ Average marks in the test $45$ $45$ Variance of distribution of marks $64$ $81$
| Section $A$ | Section $B$ | |
| Number of students | $50$ | $60$ |
| Average marks in the test | $45$ | $45$ |
| Variance of distribution of marks | $64$ | $81$ |
- Avariability of section $B >$ variability of section $A$
- Bvariability of section $A >$ variability of section $B$
- Cvariability of section $A = $ variability of section $B$
- DThe data is not sufficient to compare the variability of the sections
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Similar Questions
What is the formula for finding the coefficient of variation,given $\sigma = \text{standard deviation}$ and $\bar{x} = \text{mean} \neq 0$?
The variance of the following continuous frequency distribution is
$\begin{array}{|l|c|c|c|c|}\hline \text{Class interval} & 0-4 & 4-8 & 8-12 & 12-16 \\ \hline \text{Frequency} & 2 & 3 & 2 & 1 \\ \hline\end{array}$
$\begin{array}{|l|c|c|c|c|}\hline \text{Class interval} & 0-4 & 4-8 & 8-12 & 12-16 \\ \hline \text{Frequency} & 2 & 3 & 2 & 1 \\ \hline\end{array}$
If the variance of the frequency distribution is $160$,then the value of $c \in N$ is
$X$ $c$ $2c$ $3c$ $4c$ $5c$ $6c$ $f$ $2$ $1$ $1$ $1$ $1$ $1$
| $X$ | $c$ | $2c$ | $3c$ | $4c$ | $5c$ | $6c$ |
| $f$ | $2$ | $1$ | $1$ | $1$ | $1$ | $1$ |
Two dice $A$ and $B$ are rolled. Let the numbers obtained on $A$ and $B$ be $\alpha$ and $\beta$ respectively. If the variance of $\alpha - \beta$ is $\frac{p}{q}$,where $p$ and $q$ are coprime,then the sum of the positive divisors of $p$ is equal to
DifficultJEE MAIN 2023
View SolutionThe coefficient of variation for the frequency distribution is
$x_i$ $4$ $3$ $1$ $f_i$ $1$ $3$ $5$
| $x_i$ | $4$ | $3$ | $1$ |
| $f_i$ | $1$ | $3$ | $5$ |
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