Structures of molecules of two compounds are given below:
$(a)$ Which of the two compounds will have intermolecular hydrogen bonding and which compound is expected to show intramolecular hydrogen bonding.
$(b)$ The melting point of a compound depends on,among other things,the extent of hydrogen bonding. On this basis,explain which of the above two compounds will show a higher melting point.
$(c)$ Solubility of compounds in water depends on the power to form hydrogen bonds with water. Which of the above compounds will form hydrogen bonds with water easily and be more soluble in it?

(N/A) In compound $(i)$,intramolecular $H$-bonding is formed. Here,the $H$-atom is present between two highly electronegative oxygen atoms within the same molecule (ortho-nitrophenol).
In compound $(ii)$,intermolecular $H$-bonding is formed. In para-nitrophenol,there is a gap between the $NO_2$ and $OH$ groups,allowing $H$-bonding between the $H$-atom of one molecule and the $O$-atom of another molecule.
$(b)$ Compound $(ii)$ possesses a higher melting point because a large number of molecules are joined together by intermolecular $H$-bonds,requiring more energy to break.
$(c)$ Due to intramolecular $H$-bonding,compound $(i)$ is less able to form $H$-bonds with water,making it less soluble. Compound $(ii)$ can easily form $H$-bonds with $H_2O$ molecules,making it more soluble in water.