State whether the following statements are True or False:
$(i)$ $CH_3-CH_2^+$ is more stable than $CH_3^+$
$(ii)$ $CH_3-CH_2^+$ is less stable than $CH_3^+$
$(iii)$ $(CH_3)_3C^+$ is less stable than $CH_3^+$
$(iv)$ $(CH_3)_3C^+$ is more stable than $CH_3^+$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) The stability of carbocations is determined by the inductive effect and hyperconjugation. The order of stability is: $3^\circ > 2^\circ > 1^\circ > \text{methyl carbocation}$.
$(i)$ $CH_3-CH_2^+$ $(1^\circ)$ is more stable than $CH_3^+$ (methyl) due to the $+I$ effect of the methyl group. Statement is True $(T)$.
$(ii)$ $CH_3-CH_2^+$ is more stable than $CH_3^+$,so the statement that it is less stable is False $(F)$.
$(iii)$ $(CH_3)_3C^+$ $(3^\circ)$ is significantly more stable than $CH_3^+$ due to hyperconjugation and $+I$ effect. Statement is False $(F)$.
$(iv)$ $(CH_3)_3C^+$ is more stable than $CH_3^+$. Statement is True $(T)$.
Final answer: $(i-T, ii-F, iii-F, iv-T)$.

Explore More

Similar Questions

The shape of a carbocation is:

The increasing order of stability of the following free radicals is:

The correct order of stability of the following carbocations is:

In which pairs,the first ion is more stable than the second?

The most stable carbocation from the following is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo