Speed of a boat in standing water is 9 text{ | vedclass

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(D) Let the speed of the boat in still water be $x = 9 	ext{ km/h}$ and the speed of the stream be $y = 1.5 	ext{ km/h}$.The speed downstream is $(x

Vedclass · Accepted Answer

$24$

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(D) Let the speed of the boat in still water be $x = 9 	ext{ km/h}$ and the speed of the stream be $y = 1.5 	ext{ km/h}$.The speed downstream is $(x + y) = 9 + 1.5 = 10.5 	ext{ km/h}$.The speed upstream is $(x - y) = 9 - 1.5 = 7.5 	ext{ km/h}$.The time taken to travel $105 	ext{ km}$ downstream is $T_1 = \frac{	ext{Distance}}{	ext{Speed downstream}} = \frac{105}{10.5} = 10 	ext{ hours}$.The time taken to travel $105 	ext{ km}$ upstream is $T_2 = \frac{	ext{Distance}}{	ext{Speed upstream}} = \frac{105}{7.5} = 14 	ext{ hours}$.The total time taken is $T = T_1 + T_2 = 10 + 14 = 24 	ext{ hours}$.

Speed of a boat in standing water is $9 \text{ km/h}$ and the speed of the stream is $1.5 \text{ km/h}$. $A$ man rows to a place at a distance of $105 \text{ km}$ and comes back to the starting point. The total time taken by him is (in $\text{ hours}$)

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