Solve the given two equations and select the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For equation $I$: $x^{2} - 25 = 0 \Rightarrow x^{2} = 25 \Rightarrow x = \pm 5$.So,$x = 5$ or $x = -5$.For equation $II$: $y^{2} - 9y + 20 = 0$.Fa

Vedclass · Accepted Answer

if $x = y$ or relationship between $x$ and $y$ cannot be established.

Vedclass · Answer

(D) For equation $I$: $x^{2} - 25 = 0 \Rightarrow x^{2} = 25 \Rightarrow x = \pm 5$.So,$x = 5$ or $x = -5$.For equation $II$: $y^{2} - 9y + 20 = 0$.Factoring the quadratic equation: $y^{2} - 5y - 4y + 20 = 0 \Rightarrow y(y - 5) - 4(y - 5) = 0 \Rightarrow (y - 5)(y - 4) = 0$.So,$y = 5$ or $y = 4$.Comparing the values:If $x = 5$,then $x = y$ (when $y = 5$) and $x > y$ (when $y = 4$).If $x = -5$,then $x Since we get different results ($x = y$,$x > y$,and $x < y$) depending on the values chosen,a unique relationship between $x$ and $y$ cannot be established.

Solve the given two equations and select the correct answer from the given options.
$I.$ $x^{2}-25=0$
$II.$ $y^{2}-9y+20=0$

Similar Questions

Solve the given two equations and select the correct answer from the given options.
$I.$ $x = \sqrt{2304}$
$II.$ $y^2 = 2304$

If the sum of the roots of the equation $x^2 + px + q = 0$ is three times their difference,then which one of the following is true?

Find two consecutive positive odd integers whose squares have the sum $290.$

If $\alpha$ and $\beta$ are the roots of the equation $x^2 + 2x + 4 = 0$,then $\frac{1}{\alpha^3} + \frac{1}{\beta^3}$ is equal to

The number of integral values of $a$ for which $x^2 - (a - 1)x + 3 = 0$ has both roots positive and $x^2 + 3x + 6 - a = 0$ has both roots negative is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Solve the given two equations and select the correct answer from the given options.$I.$ $x^{2}-25=0$$II.$ $y^{2}-9y+20=0$