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(B) For equation $I: 3x^2 + 5x - 2 = 0$Factorizing: $3x^2 + 6x - x - 2 = 0$$3x(x + 2) - 1(x + 2) = 0$$(3x - 1)(x + 2) = 0$So,$x = 1/3$ or $x = -2$.For

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if $x < y$

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(B) For equation $I: 3x^2 + 5x - 2 = 0$Factorizing: $3x^2 + 6x - x - 2 = 0$$3x(x + 2) - 1(x + 2) = 0$$(3x - 1)(x + 2) = 0$So,$x = 1/3$ or $x = -2$.For equation $II: 2y^2 - 7y + 5 = 0$Factorizing: $2y^2 - 2y - 5y + 5 = 0$$2y(y - 1) - 5(y - 1) = 0$$(2y - 5)(y - 1) = 0$So,$y = 5/2 = 2.5$ or $y = 1$.Comparing the values:$x_1 = 0.33, x_2 = -2$$y_1 = 2.5, y_2 = 1$In all cases,$x < y$.

Solve the given two equations and select the correct option.
$I. 3x^2 + 5x - 2 = 0$
$II. 2y^2 - 7y + 5 = 0$

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Solve the given two equations and select the correct option.$I. 3x^2 + 5x - 2 = 0$$II. 2y^2 - 7y + 5 = 0$