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(C) Step $1$: Solve for $x$ from equation $I$.$x^{3} - 468 = 1729$$x^{3} = 1729 + 468$$x^{3} = 2197$$x = \sqrt[3]{2197} = 13$Step $2$: Solve for $y$ f

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if $x \ge y$

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(C) Step $1$: Solve for $x$ from equation $I$.$x^{3} - 468 = 1729$$x^{3} = 1729 + 468$$x^{3} = 2197$$x = \sqrt[3]{2197} = 13$Step $2$: Solve for $y$ from equation $II$.$y^{2} - 1733 + 1564 = 0$$y^{2} - 169 = 0$$y^{2} = 169$$y = \pm 13$Step $3$: Compare $x$ and $y$.We have $x = 13$ and $y = 13$ or $y = -13$.In the first case,$x = y$ $(13 = 13)$.In the second case,$x > y$ $(13 > -13)$.Combining both cases,we get $x \ge y$.

Solve the given two equations and select the correct answer from the given options.
$I.$ $x^{3} - 468 = 1729$
$II.$ $y^{2} - 1733 + 1564 = 0$

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Solve the given two equations and select the correct answer from the given options.$I.$ $x^{3} - 468 = 1729$$II.$ $y^{2} - 1733 + 1564 = 0$