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(B) First,simplify the given equations:Equation $1$: $7y + 21 - 2x - 4 = 14 \implies -2x + 7y = -3$Equation $2$: $4y - 8 + 3x - 9 = 2 \implies 3x + 4y

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$(5, 1)$

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(B) First,simplify the given equations:Equation $1$: $7y + 21 - 2x - 4 = 14 \implies -2x + 7y = -3$Equation $2$: $4y - 8 + 3x - 9 = 2 \implies 3x + 4y = 19$To eliminate $x$,multiply Equation $1$ by $3$ and Equation $2$ by $2$:$-6x + 21y = -9$$6x + 8y = 38$Adding the two equations: $29y = 29 \implies y = 1$Substitute $y = 1$ into Equation $2$: $3x + 4(1) = 19 \implies 3x = 15 \implies x = 5$Thus,the solution is $(x, y) = (5, 1)$.

Solve the following pairs of equations by the method of elimination:
$7(y+3)-2(x+2)=14$
$4(y-2)+3(x-3)=2$

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Solve the following pairs of equations by the method of elimination:$7(y+3)-2(x+2)=14$$4(y-2)+3(x-3)=2$