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(C) Given equations are:$(1) \ 9x + 7y = 55$$(2) \ 7x + 9y = 57$Adding equations $(1)$ and $(2)$:$(9x + 7x) + (7y + 9y) = 55 + 57$$16x + 16y = 112$Div

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$(3, 4)$

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(C) Given equations are:$(1) \ 9x + 7y = 55$$(2) \ 7x + 9y = 57$Adding equations $(1)$ and $(2)$:$(9x + 7x) + (7y + 9y) = 55 + 57$$16x + 16y = 112$Dividing by $16$:$x + y = 7 \quad (3)$Subtracting equation $(2)$ from $(1)$:$(9x - 7x) + (7y - 9y) = 55 - 57$$2x - 2y = -2$Dividing by $2$:$x - y = -1 \quad (4)$Adding equations $(3)$ and $(4)$:$(x + y) + (x - y) = 7 + (-1)$$2x = 6 \implies x = 3$Substituting $x = 3$ in equation $(3)$:$3 + y = 7 \implies y = 4$Thus,the solution is $(x, y) = (3, 4)$.

Solve the following pairs of equations by the method of elimination:
$9x + 7y = 55$
$7x + 9y = 57$

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Solve the following pairs of equations by the method of elimination:$9x + 7y = 55$$7x + 9y = 57$