Solve the following inequality and represent it on a number line: $\frac{x-1}{2}+5 \geq \frac{2x-1}{3}+15$

(N/A) Given inequality: $\frac{x-1}{2}+5 \geq \frac{2x-1}{3}+15$
Subtract $5$ from both sides: $\frac{x-1}{2} \geq \frac{2x-1}{3}+10$
Multiply by $6$ to clear denominators: $3(x-1) \geq 2(2x-1) + 60$
Expand: $3x-3 \geq 4x-2+60$
Simplify: $3x-3 \geq 4x+58$
Rearrange terms: $-3-58 \geq 4x-3x$
Result: $-61 \geq x$ or $x \leq -61$
The solution set is $(-\infty, -61]$.
The number line representation shows a solid circle at $-61$ with a line extending to the left.