The solution of the differential equation $(x + \log y)dy + y\,dx = 0$ is:
- A$xy + y\log y = c$
- B$xy + y\log y - y = c$
- C$xy + \log y - x = c$
- DNone of these
Explore More
Similar Questions
The solution of the differential equation $\frac{dy}{dx} + 2y = e^{-x}$ is
The integrating factor of the differential equation $(2x + 3y^2) dy = y dx$ $(y > 0)$ is
Solve the differential equation $\left(\tan ^{-1} y-x\right) d y=\left(1+y^{2}\right) d x$.
Medium
View SolutionThe general solution of the differential equation $\frac{dy}{dx} + \frac{y \ln y}{x} = \frac{y(\ln y)^2}{x^2}$ is (where $C$ is an arbitrary constant):
The solution of the equation $\frac{dy}{dx} + 2y \tan x = \sin x$ satisfying $y = 0$ when $x = \frac{\pi}{3}$ is:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo