Solubility product of a salt $AB$ is $1 \times 10^{-8}$ in a solution in which the concentration of $A^{+}$ ions is $10^{-3} \ M$. The salt will precipitate when the concentration of $B^{-}$ ions is kept
- Abetween $10^{-8} \ M$ to $10^{-7} \ M$
- Bbetween $10^{-7} \ M$ to $10^{-8} \ M$
- C$> 10^{-5} \ M$
- D$< 10^{-8} \ M$
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