Solid carbon,CaO and CaCO_3 are mixed and all | vedclass

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(B) For the first equilibrium: $CaCO_3(s) ightleftharpoons CaO(s) + CO_2(g)$,the equilibrium constant is $K_{p1} = P_{CO_2} = 0.08 	ext{ atm}$.For

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(B) For the first equilibrium: $CaCO_3(s) ightleftharpoons CaO(s) + CO_2(g)$,the equilibrium constant is $K_{p1} = P_{CO_2} = 0.08 	ext{ atm}$.For the second equilibrium: $C(s) + CO_2(g) ightleftharpoons 2CO(g)$,the equilibrium constant is $K_{p2} = \frac{P_{CO}^2}{P_{CO_2}} = 2$.Substituting the value of $P_{CO_2}$ from the first equilibrium into the second expression:$P_{CO}^2 = K_{p2} 	imes P_{CO_2} = 2 	imes 0.08 = 0.16 	ext{ atm}^2$.Taking the square root,$P_{CO} = \sqrt{0.16} = 0.4 	ext{ atm}$.Converting to the required format: $0.4 	ext{ atm} = 4 	imes 10^{-1} 	ext{ atm}$.Thus,the partial pressure of $CO$ is $4 	imes 10^{-1} 	ext{ atm}$.

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